1. If 10.0 g of a radioactive isotope has a half life of 10 hours, the half life of 4.0 g of the same substance is
a) 2.5 hrs
b) 5 hrs
c) 10 hrs
d) 40 hrs
Showing posts with label Energetics. Show all posts
Showing posts with label Energetics. Show all posts
Monday, December 24, 2007
Monday, December 17, 2007
Past JEE Questions Ch.6
JEE Question 2007 paper II
For the process (water becoming steam) H-2O(l)(1 bar, 373 K) --> H-2O(g)(1 bar, 373 K), the correct set of thermodynamic parameters is
(A) ∆G=0,∆S= + ve
(B)∆G=0,∆S= -ve
(C)∆G=+ve,∆S=0
(D)∆G=-ve, ∆S= + ve
Solution: A
The answer is A because, because at 100 degree C, the steam and water mixture is at equilibrium. Hence ΔG = 0(G = H - TS), and ΔS is positive. Why? when liquid becomes gas, there is more disorder. More entropy.
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For the process (water becoming steam) H-2O(l)(1 bar, 373 K) --> H-2O(g)(1 bar, 373 K), the correct set of thermodynamic parameters is
(A) ∆G=0,∆S= + ve
(B)∆G=0,∆S= -ve
(C)∆G=+ve,∆S=0
(D)∆G=-ve, ∆S= + ve
Solution: A
The answer is A because, because at 100 degree C, the steam and water mixture is at equilibrium. Hence ΔG = 0(G = H - TS), and ΔS is positive. Why? when liquid becomes gas, there is more disorder. More entropy.
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